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Russ discovers at the end of the summer that his radiator antifreeze solution has dropped below the safe level. if the radiator contains 4 gallons of a 25% solution, how many gallons of pure antifreeze must he add to bring it up to a desired 50% solution?

User Dlchambers
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8.3k points

1 Answer

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Let's call x the pure antifreeze in gallons. This means 4 + x represents the new quantity of pure antifreeze.

According to the problem, 25% of the solution represents 4 gallons and 50% of the solution represents the new quantity of antifreeze.

Based on the given information, we can express the following.


0.25(4)+x=0.50(4+x)

Let's solve for x.


\begin{gathered} 1+x=2+0.50x \\ x-0.50x=2-1 \\ 0.50x=1 \\ x=(1)/(0.50) \\ x=2 \end{gathered}

Therefore, he needs to add 2 gallons of pure antifreeze.

User Andrew Bezzub
by
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