Question

The volume of a gas is 7.6 L when the temperature is 8.00ºC. If th.e temperature is increased to 22.0º without changing the pressure, what is the new volume?

Answer 1

`7.98\text{ L}`

Step-by-step explanation:

Here, we want to get the new volume of the gas without changing the pressure

From Charles' law, we know that temperature and volume are directly proportional

We have that as:

`(V_1)/(T_1)\text{ = }(V_2)/(T_2)`

From the question, we have the given values (we have to convert the given temperature values to Kelvin by adding 273.15 K) as:

V1 is 7.6 L

V2 = ?

T1 is 8 + 273.15 = 281.15 K

T2 is 22 + 273.15 = 295.15 K

Substituting the values, we have that as follows:

`\begin{gathered} (7.6)/(281.15)\text{ = }(V_2)/(295.15) \\ \\ V_2\text{ = }(7.6*295.15)/(281.15)\text{ = 7.98 l} \end{gathered}`