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Draw the image of ABC under the translation (x, y) + (x + 2, Y + 2). y 6+ 5- 3 2 1+ -7 -6 5 4 3 2 2 3 5 6 7 -2 B -3- -5- -6 2 of 4

Draw the image of ABC under the translation (x, y) + (x + 2, Y + 2). y 6+ 5- 3 2 1+ -7 -6 5 4 3 2 2 3 5 6 7 -2 B-example-1

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The translation is (x,y)->(x+2,y+2). To draw the ABC under the translation we have to translate the points A(-2,2), B(-5,-2) and C(-6,4).

The translation correspond to add 2 units to the x-value and 2 units to the y-value. So the triangle ABC transform to A'B'C', the points A', B' and C' are:


\begin{gathered} A(-2,2)\to A^(\prime)(-2+2,2+2)=A^(\prime)(0,4) \\ B(-5,-2)\to B^(\prime)(-5+2,-2+2)=B^(\prime)(-3,0) \\ C(-6,4)\to C^(\prime)(-6+2,4+2)=C^(\prime)(-4,6) \end{gathered}

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