The answer can be found by assuming that we have an arithmetic progression that stars in 53 with a common difference of 7. The equation for the sum of an arithmetic progression up to n terms is given by:
![s_n=(n)/(2)(2a+(n-1)d)](https://img.qammunity.org/2023/formulas/mathematics/high-school/7k78orp46i4glq7esk8782ph5s3qflqnao.png)
Where, for this case
![a=53\text{ , }n=20\text{ and }d=7](https://img.qammunity.org/2023/formulas/mathematics/high-school/4nyje16l5lm94t140sb9zcdvlsq2n1qqgc.png)
So, applying the equation with these data, we obtain:
![\begin{gathered} s_(20)=(20)/(2)(2(53)+(20-1)7) \\ s_(20)=10(106+19(7)) \\ s_(20)=10(106+19(7))=10(239)=2390 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/6msql0twkrvs0dz6e54oyi11nf8qswiy73.png)
Thus, the sum up to 20 terms of the given series is 2390.