Question

Sin 0 = -48/73and cos 0 = 55/73. Find tan 0.

Answer 1

`\tan \theta=-(48)/(55)`

Step-by-step explanation:

Given that;

`\begin{gathered} \sin \theta=-(48)/(73) \\ \cos \theta=(55)/(73) \end{gathered}`

Recall that;

`\begin{gathered} \sin \theta=(opposite)/(hypotenuse) \\ \cos \theta=(adjacent)/(hypotenuse) \\ \tan \theta=(opposite)/(adjacent) \\ \tan \theta=(\sin \theta)/(\cos \theta) \end{gathered}`

Substituting the given values of sine and cosine;

`\begin{gathered} \tan \theta=(-(48)/(73))/((55)/(73))=-(48)/(73)*(73)/(55) \\ \tan \theta=-(48)/(55) \end{gathered}`

Therefore;

`\tan \theta=-(48)/(55)`