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NIKUNJ KOTHIYA · Answer 1 · 2023-02-12T08:59:19+0000

Answer:

0.74 grams

Explanations

Given the following parameters

Volume of Ca(OH)₂ = 100mL = 0.1L

Molarity of Ca(OH)₂ = 100mM = 0.1M

Determine the moles of Ca(OH)₂

$\begin{gathered} moles\text{ of Ca\lparen OH\rparen}_₂=molarity* volume \\ moles\text{ of Ca\lparen OH\rparen}_₂=(0.1mol)/(L)*0.1L \\ moles\text{ of Ca\lparen OH\rparen^^^^2082=0.01mole} \end{gathered}$

Calculate the mass of Ca(OH)₂

Molar mass of Ca(OH)2 = 20 + (16*2) + (2*1.01)

Molar mass of Ca(OH)2 = 40 +32 + 2.02

Molar mass of Ca(OH)2 = 74.02g/mol

$\begin{gathered} Mass\text{ of Ca\lparen OH\rparen}_2=moles* molar\text{ mass} \\ \text{Mass of Ca\lparen OH\rparen}__2=0.01mole*74.02(g)/(mole) \\ Mass\text{ of Ca\lparen OH\rparen}_2\approx0.74grams \end{gathered}$

Hence the amount of mass of Ca(OH)2 needed to make 100 ml of a 100mM solution is 0.74 grams

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