Six jars contain a total of 2727 candy bars. If each jar contains nine more candy bars than the previous jar, how much candy is in each jar?
Let
x -----> number of candy bars in the first jar
so
we have the sequence
x , (x+9), x+18,x+27, x+36,x+45
therefore
x+(x+9)+(x+18)+(x+27)+(x+36)+(x+45)=2.727
solve for x
6x+135=2,727
6x=2,727-135
6x=2,592
x=432
therefore
First jar -----> 432 candy bars
Second jar=432+9=441 candy bars
Third jar=441+9=450 candy bars
Fourth jar=450+9=459 candy bars
Fifth jar=459+9=468 candy bars
Sixth jar=468+9=477 candy bars