The volume of recangular prism can be calculated as:
![V=w\cdot l\cdot h](https://img.qammunity.org/2023/formulas/mathematics/college/zjf8vm3j0vz6uat7prvj2r1l2hyfpl44tm.png)
V: volume
w: width
l: length
h: height
The box heigth has been increased by 15%, this means that to the original heigth 0.15% of it has been added:
Let "x" represent the original height of the box
![\begin{gathered} h=x+0.15x \\ h=1.15x \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/xirqh622415npauy6cc9rrks91wj62vu0w.png)
The box length has been increased by 25%, this means that to the original length, 0.25 more has been added
Let "y" represent the length of the box:
![\begin{gathered} l=y+0.25y \\ l=1.25y \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/1yk70gldvmwapc5ouda6gngacboqzir8sy.png)
Let "z" represent the original width of the box.
The original volume of the box can be calculated as:
![V_{\text{old}}=xyz](https://img.qammunity.org/2023/formulas/mathematics/college/h1l8ejyswl4ulxln3numj9edyo5rn5bbcg.png)
And the new volume of the box can be calculated as
![V_{\text{new}}=1.15x\cdot1.25y\cdot z](https://img.qammunity.org/2023/formulas/mathematics/college/tnjv3306f2oz56f80g28tvin9afcx474md.png)
To calculate the percentage increase you have to subtract the old volume from the new one and divide it by the old volume.
![\begin{gathered} \text{Increase}=\frac{V_{\text{new}}-V_{\text{old}}}{V_{\text{old}}}_{} \\ \text{Increase}=((1.15x\cdot1.25y\cdot z)-(xyz))/(xyz) \\ \text{Increase=}(2.4xyz-xyx)/(xyz) \\ \text{Increase}=(1.4xyz)/(zyx) \\ \text{Increase}=1.4 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/n0ibw4hapt3cmiy2a5wt0qfhql2qy8g384.png)
The 1 represents the original volume, so that the box volume was increased 0.4 of its original volume.
Multiply it by 100 and the percentaje is 40%