SOLUTION
Let the two integers be x and y.
Now, the product of x and y, is 80, that is

The quotient of x and y is 5, that is

From equation 2, make x, the subject, we have

Now substitute the x for 5y into equation 1, we have
![\begin{gathered} xy=80 \\ 5y* y=80 \\ 5y^2=80 \\ \text{dividing by 5} \\ y^2=(80)/(5) \\ y^2=16 \\ \text{take square root of both sides } \\ \sqrt[]{y^2}=\sqrt[]{16} \\ \text{square cancels root} \\ y=4 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/rh7fdbcjqpf80m19j94qnv3xcfnr7ao9x4.png)
Now substitute y for 4 into any of the equations.
Let us use equation 1 again, we have

Hence the answer is 4, 20