Question

Estimate the electric field in the membrane wall of a living cell. Assume the wall is 14 nmnm thick and has a potential of 0.11 VV across it.

Answer 1

The electric field in the membrane wall of a living cell is 7.857 x 10⁶ V/m.

Step-by-step explanation:

Given;

thickness of the membrane wall, d = 14 nm = 14 x 10⁻⁹ m

potential of the membrane wall, V = 0.11 V

The electric field in the membrane wall of a living cell is calculated as;

`E = (V)/(d) \\\\E = (0.11)/(14 * 10^(-9)) \\\\E = 7.857 * 10^6 \ V/m`

Therefore, the electric field in the membrane wall of a living cell is 7.857 x 10⁶ V/m.