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On a standardized exam, the scores are normally distributed with a mean of 550 anda standard deviation of 40. Find the Z-score of a person who scored 538 on the exam.Answer:Submit Answer

User Karask
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1 Answer

6 votes

For any normally distributed data, we can use the the formula for z-score as follows:


z=(x-\mu)/(\sigma)

Where x is the data, in this case 538, μ is the mean, in this case 550, and σ is the standard deviation, in this case 40. z is the z-score.

So, we can just substitute our values and evaluate:


\begin{gathered} z=(538-550)/(40) \\ z=(-12)/(40) \\ z=-0.3 \end{gathered}

Thus, the z-score is -0.3.

User Zelgadis
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