Question

g A particle is in the excited state of a quantum simple harmonic oscillator well. A photon with a frequency of Hz is emitted as the particle moves to the excited state. What is the minimum photon frequency required for this particle to make a quantum jump from the ground state of this well to the excited state

Answer 1

ΔE = h f

Step-by-step explanation:

The energy for a quantum harmonic oscillator is given by the expression

E = (ν + ½) h f

where ν is an integer and ½ is the ground state energy and zero point,

In this case, if the emission frequency is f, the position between the initial (excited) and final (ground state) states is

DE = (v_f- v₀) hf

the minimum emitted frequency is

v_f = 1

v₀ = 0

ΔE = h f