13.7k views
3 votes
The surface area of a cylinder is 325 in2 inches. Thelateral area is 200 in2.What is the radius of each of the bases?Round the answer to the nearest tenth.

User BoRRis
by
3.2k points

1 Answer

6 votes

The surface area of the cylinder = lateral area + 2 base area

Since the surface area = 325 in^2

Since the lateral area = 200 in^2

Subtract them to find 2 base area

2 base area = 325 - 200 = 125

Divide it by 2 to find the base area


\begin{gathered} b\mathrm{}A=(125)/(2) \\ b\mathrm{}A=62.5 \end{gathered}

Since the base of the cylinder is a circle

Since the area of the circle is


b\mathrm{}A=\pi* r^2

Substitute bA by 62.5


62.5=\pi* r^2

Divide both sides by pi


(62.5)/(\pi)=r^2

Take a square root for both sides


\begin{gathered} \sqrt[]{(62.5)/(\pi)}=r \\ r=4.46031092 \end{gathered}

Round it to the nearest tenth

r = 4.5 inches

User Mindmatters
by
4.0k points