115k views
5 votes
Could you please help

1 Answer

4 votes

The figure shown is made up of a right angled triangle and a rectangle.

The triangle has a base of 8cm, because its placed on the length of the rectangle which is 16cm and the cut off portion is 8cm, so that leaves the triangle with a base of 8cm (16 - 8). The vertical height of the triangle is 6cm (that is 13cm - 7cm).

The rectangle has a length of 16cm and a width of 7cm.

Therefore, the area is calculated as follows;


\begin{gathered} \text{Areaof rectangle=L x W} \\ \text{Area}=16*7 \\ \text{Area}=112\operatorname{cm} \\ \text{Area of triangle=}(1)/(2)* bh \\ \text{Area}=(1)/(2)*8*6 \\ \text{Area}=24\operatorname{cm} \\ \text{Area of figure=area of rectangle + Area of triangle} \\ \text{Area}=112+24 \\ \text{Area}=136\operatorname{cm} \end{gathered}

User Fedor
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories