A chemist has 3 liters of a 40% alcohol solution. How much should he pour out and then replace with pure alcohol to get 3 liters of a 75% alcohol solution?

Question

asked Oct 2, 2023 44.2k views

1 Answer

Frast · Answer 1 · 2023-10-09T02:22:18+0000

Given:

3 liter of a 40% alcohol solution.

$\begin{gathered} =3*(40)/(100) \\ =3*0.4 \\ =1.2 \end{gathered}$

Then here 1.2 liter of alcohol.

3 liter of a 75% alcohol solution.

$\begin{gathered} =3*(75)/(100) \\ =2.25 \end{gathered}$

So 2.25 liter pure alcohol required in 3 liter of solution.

for add 2.25 liter alcohol solution

$\begin{gathered} =2.25-1.2 \\ =1.05 \end{gathered}$

So the 1.05 liter alochol required to maintain the 75% alcohol solution.