235k views
3 votes
I need help with a word problem! I need to find the probability.A gambler places a bet on a horse race. To win, he must pick the top three finishers in order. Seven horses of equal ability are entered in the race. Assuming the horses finish in a random order, what is the probability that gambler will win his bet?

1 Answer

4 votes

ANSWER

1/35

Step-by-step explanation

First we have to find how many ways you can pick 3 horses out of 7. For the first place you have 7 horses that can be there. For the second place, you have 6 horses (you already placed one horse) and for the third place you have 5 horses. The number of ways to pick 3 horses - in order - from 7 horses is:


7*6*5=210

Now we want to know the permutations for 3 horses. Once you have picked one combination out of the 210 combinations of 3 horses, there are many ways to arrange them. This is:


3!=3*2*1=6

Let 'A' be the event where the gambler wins his bet:


P(A)=(6)/(210)

We can simplify this fraction:


P(A)=(1)/(35)

User Octane
by
4.3k points