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19 votes
19 votes
F(n)=45⋅(4/5)^n−1
complete the recursive formula of f(n)

User Advay Rajhansa
by
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2 Answers

24 votes
24 votes

Answer:

45

4/5

Explanation:

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User Evil Buck
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24 votes
24 votes

F(1) = 45

f(n) = f(n-1) * 4/5

Explanation:

f(n) = 45 x (4/5)ⁿ⁻¹

f(1) = 45 x (4/5)¹⁻¹ = 45 x (4/5)⁰ = 45 x 1 = 45

f (n-1) = 45 x (4/5)ⁿ⁻¹⁻¹ = 45 x (4/5)ⁿ⁻²

f(n) = f(n-1) * (4/5)¹ = 45 x (4/5) ⁿ⁻²⁺¹ = 45 x (4/5)ⁿ⁻¹

User Waynetech
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