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What is the domain of function g(x)=x+1/(x+1)(x-1)?

User Andho
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1 Answer

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Given the function:


g(x)=(x+1)/((x+1)(x-1))

Let's find the domain of the function.

The domain is all set of x values which makes the function defined.

To find the domain, set the denominator to zero and solve for x.

We have:

(x + 1)(x - 1) = 0

Set the individual factors to zero and solve for x.

x + 1 = 0

Subtract 1 from both sides:

x + 1 - 1 = 0 - 1

x = -1

x - 1 = 0

Add 1 to both sides:

x - 1 + 1 = 0 + 1

x = 1

Therefore, the domain of the function in interval notation is:


\mleft(-\infty,-1\mright)\cup(-1,1)\cup(1,\infty)

ANSWER:


\mleft(-\infty,-1\mright)\cup(-1,1)\cup(1,\infty)

User Tim Weber
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