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(Pre-Algebra)Consider the followingPoint (-1,4) Line x + 6 = 0 (Question in photo)

(Pre-Algebra)Consider the followingPoint (-1,4) Line x + 6 = 0 (Question in photo-example-1
User Virgen
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1 Answer

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a) We have to write a parallel line to x + 6 = 0 that passes through (-1,4).

Parallel lines always have the same slope.

In this case, this is a vertical line defined as:


\begin{gathered} x+6=0 \\ x=-6 \end{gathered}

NOTE: vertical lines have undefined slopes, as they approach infinite when tried to calculate them.

Then, we have to find the vertical line that passes through (-1,4).

If (-1,4) is partof the line, then x has to be equal to -1.

As x takes only one value for a vertical line, then we can define the line as x = -1 or x + 1 = 0, which is equivalent.

b) We have to find the line that passes through (-1,4) that is perpendicular to x + 6 = 0.

Perpendicular lines have slopes that are negative reciprocals with the original slope.

In this case, as the original line is vertical (with an undefined slope), a perpendicular line will be an horizontal line (with slope m = 0).

Horizontal lines can be expressed as y = k, where k is a constant.

In this case, it has to pass through (-1,4). As y has to be equal to 4 at that point, it will be equal to 4 for all the remaining points.

Then, we can write the equation as:


\begin{gathered} y=4 \\ y-4=0 \end{gathered}

Answer:

a) x + 1 = 0

b) y - 4 = 0

User Pacerier
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