We are given the following equation system:

The slope-intercept form of a linear equation is the following:

Taking equation (1):

Now we solve for "y". To do that we add 4x to both sides:

Now, taking equation (2):

Adding 8x to both side:

Dividing both sides by 8:

The graph of both equations are the following:
Since the graphs of each line do not have the same slope, they are a consistent system and are independent. The solution is the point where the two lines intercept, that is (x,y) = (-6,-8).