Recall that to compute the equation of a line we have to have two points on the line, once we have two points we can use the following formula for the equation (unless it is a vertical line):
![y-y_1=(y_1-y_2)/(x_1-x_2)(x-x_1),](https://img.qammunity.org/2023/formulas/mathematics/high-school/c26f9cjtsggty63xqx859dvmz3lnquzy3l.png)
where (x₁,y₁) and (x₂,y₂) are two points on the line.
Now, notice that points (0,-1) and (3,2) are on line n, therefore its equation is:
![y-2=(2-(-1))/(3-0)(x-3)\text{.}](https://img.qammunity.org/2023/formulas/mathematics/high-school/xc2c6j8qfuf85wdzerv1t1wnnvkc7u4ulj.png)
Simplifying the above equation we get:
![y-2=(x-3)\text{.}](https://img.qammunity.org/2023/formulas/mathematics/high-school/ihw3m113ofzlp6wa7k5exgsu21qedl8330.png)
Two points on line m are: (0,4) and (1,2), therefore, its equation is:
![y-4=(4-2)/(0-1)(x-0)\text{.}](https://img.qammunity.org/2023/formulas/mathematics/high-school/37ulqf9n23q3za58j1scdty79skwnmo3gx.png)
Simplifying the above equation we get:
![y-4=-2x\text{.}](https://img.qammunity.org/2023/formulas/mathematics/high-school/zg9tm8i5dklx91b0hvzw7k7x0vhay58mj9.png)
Since line l is horizontal all its points will have the same y entry y=5, therefore, its equation is:
![y=4.](https://img.qammunity.org/2023/formulas/mathematics/high-school/i8krpbdldtlw4uf9cdnb2jtsyq2lyv86nl.png)
Now, finally, when we have a vertical line its equation will be of the form x=k, where k is the x-entry of the points on the line. Notice that line p is a vertical line, and one point on the line is (-4,0), therefore its equation is:
![x=-4.](https://img.qammunity.org/2023/formulas/mathematics/high-school/rcq18ao6zrzq08hgfw85g316nkth44yy3g.png)
Answer: