Question

A 65.0 kg skier slides down a 37.20 slope with mu = 0.107.

What is the friction force?

Answer 1

magnitude of friction force- 54.3

friction force- -54.2

Step-by-step explanation:

Answer 2

54.3N

Step-by-step explanation:

The normal force is perpendicular to the slope, so:

Normal Force = cos(37.2)(9.8*65).......507.39N

F(friction)=mu*F(normal)

F(friction)=(0.107)(507.39)

F(friction)=54.3N