Question

An object is initially moving at an unknown velocity. It accelerates at a rate of 2.0 m/s^2 to a new velocity of 45 m/s in 10s. What was the initial velocity? v = vo + at

Answer 1

Given data:

* The final velocity of the object is 45 m/s.

* The acceleration of the object is,

`a=2ms^(-2)`

* The time taken by the object to acquire the final velocity is 10 s.

Solution:

The initial value of the velocity by the kinematic equation is,

`\begin{gathered} v=v_o+at \\ v_o=v-at \end{gathered}`

where v is the final velocity, v_o is the initial velocity, t is the time taken by the object to acquire the new velocity,

Substituting the known values,

`\begin{gathered} v_o=45-2*10_{} \\ v_o=45-20_{} \\ v_o=25ms^(-1) \end{gathered}`

Thus, the initial velocity of the object is 25 meter per second.