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TAHA SULTAN TEMURI · Answer 1 · 2023-03-08T15:03:10+0000

Solution:

Given:

$(5)/(2),(3)/(2),\sqrt[]{4},-2,-3,(4)/(3)$

An integer is a whole number that can be positive, negative, or zero. An integer is not a fractional number.

Hence,

$\begin{gathered} (5)/(2)\text{ is a rational number expressed as the ratio of two integers. It is a fraction.} \\ \\ (3)/(2)\text{ is a rational number expressed as the ratio of two integers. It is a fraction.} \\ \\ \sqrt[]{4}\text{ is the square root of a p}\operatorname{erf}ect\text{ square.} \\ \sqrt[]{4}=\pm2 \\ \text{The square root of p}\operatorname{erf}ect\text{ squares are integers.} \\ \text{Hence,} \\ \sqrt[]{4}\text{ is an integer} \\ \\ -2\text{ is an integer because it is a negative whole number} \\ \\ -3\text{ is an integer because it is a negative whole number} \\ \\ (4)/(3)\text{ is a rational number expressed as the ratio of two integers. It is a fraction.} \end{gathered}$

Therefore, the numbers that are integers from the set are;

$\begin{gathered} \sqrt[]{4} \\ -2 \\ -3 \end{gathered}$

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