Question

what's is Brewster's angle for a diamond submerged in water if the light is hitting the diamond (n= 2.42) while traveling in the water?

Answer 1

61.21°

Step-by-step explanation

The refractive index of water is n = 1.33

In this problem the light travels from water to diamond, so we have to find the angle from the vertical form,

`\tan \theta p=\frac{n_{\text{diamond}}}{n_{\text{water}}}`

Replacing the indices,

`\tan \theta_p=(2.42)/(1.33)`

And solving for θ,

`\theta_p=\tan ^(-1)((2.42)/(1.33))`
`\theta_p\approx61.21`

Brewster's angle is 61.21°