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What is the molecular formula of the compound with a molecular weight of 112 g/mol and percent composition: 85.6% C and 14.4% H?C8H16CH2C4H8C2H4

User Greggreg
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1 Answer

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To find the molecular formula of this compound, what we're going to do is to follow up the steps:

Step 1: Pass all the percentages to grams. This is, just to change the unit:

Step 2: Divide each mass by respective molar mass to obtain the moles of each element:

Step 3: Divide all the amounts in moles through by smaller value obtained:

These are the subscripts for C and H respectively. Thus our empirical formula is CH2. We're asked to find the molecular formula so, we could use the fact that the compound has a molecular weight of 112 g/mol. If we analyze, CH2 has a molecular weight of 14g/mol, so:

Step 4: We're going to divide the molecular weight of the compound with molecular formula through by the molecular weight of the compound with empirical formula:

This means that our molecular formula will be eight times the subscripts of the empirical formula. Therefore, the answer is:

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User Colin Young
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