When multiplying two square roots, multiply the numbers inside the roots and then solve the problem:
![\sqrt[]{a}\cdot\sqrt[]{b}=\sqrt[]{a\cdot b}](https://img.qammunity.org/2023/formulas/mathematics/college/ktymxcxst128uvfstavh79ma2rodn9t0cf.png)
In this problem:
![\sqrt[]{-180}\cdot\sqrt[]{10}=\sqrt[]{-1800}](https://img.qammunity.org/2023/formulas/mathematics/college/wylfmxpbeorooobw6ya89k1d4i6de56amw.png)
Using the same rule above, you can divide the square root into 1800 and -1:
![\sqrt[]{-1800}=\cdot\sqrt[]{1800}\cdot\sqrt[]{-1}](https://img.qammunity.org/2023/formulas/mathematics/college/mrh6gvq7f5snhpeivnhmcbcvfw90mzvurb.png)
Using i = √-1
![\sqrt[]{1800}\cdot i](https://img.qammunity.org/2023/formulas/mathematics/college/hupcdiu9wwdct9eh6ht3srzlxaqpo6sjm4.png)
Now, let's factor 1800:
1800 |2
900 |2
450 |2
225 |3
75 |3
25 |5
5 |5
1
So, 1800 = 2*2*2*3*3*5*5
Then,
![\begin{gathered} \sqrt[]{1800}i=\sqrt[]{2\cdot2\cdot2\cdot3\cdot3\cdot5\cdot5}i \\ =2\cdot3\cdot5\cdot\sqrt[]{2}i \\ =30i\sqrt[]{2} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ykbygynye6q0j3vv40j1u4n5rc09m8rskh.png)
Answer: 30i√2.