Question

If you dilute 20.0 mL of a 3.5M solution to make 100.0 mL of solution, what is the molarity of the dilute solution?

Answer 1

0.7 M

Step-by-step explanation

Given:

The initial volume of the solution, V₁ = 20.0 mL = 0.02 L

The initial molarity of the solution, C₁ = 3.5 M

The final volume of the solution, V₂ = 100.0 mL = 0.10 L

What to find:

The final molarity of the dilute solution, C₂.

Step-by-step solution:

The final molarity of the dilute solution, C₂ can be calculated using the dilution formula below:

`\begin{gathered} C_1V_1=C_2V_2 \\ \\ \Rightarrow C_2=(C_1V_1)/(V_2) \end{gathered}`

Put the given parameters into the formula:

`C_2=\frac{0.02\text{ }L*3.5\text{ }M}{0.10\text{ }L}=0.7\text{ }M`

Therefore, the molarity of the dilute solution is 0.7 M