Question

If t(d)=3d+1 and d(n)=4n+2, what is t(d(n) when n=5

Answer 1

t(d(n)) = 67 when n = 5

Step-by-step explanation

t(d) = 3d + 1

d(n) = 4n + 2

t[d(n)] menas we evaluated t(d), but instead of d, we put in d(n)

t[d(n)] = 3[d(n)] + 1

= 3(4n + 2) + 1

= 12n + 6 + 1

= 12n + 7

when n = 5

t[d(n)] = 12n + 7 = 12(5) + 7 = 60 + 7 = 67

Hope this Helps!!!