Given:
![xy+12=0](https://img.qammunity.org/2023/formulas/mathematics/college/txg0vz41ljdntum1x7tlxrl9o6jx2d81m6.png)
Required:
We need to graph the given equation.
Step-by-step explanation:
Set x =1 and substitue in the given equation to find the point lie of the graph.
![(1)y+12=0](https://img.qammunity.org/2023/formulas/mathematics/college/1kobcf0xjlzkkk3i07uyts3x1sakn6okz6.png)
![y+12=0](https://img.qammunity.org/2023/formulas/mathematics/college/clsqw43q3q5cvs8qy9ivjpdolbqzu5lntf.png)
Substract 12 from both sides of the equation.
![y+12-12=0-12](https://img.qammunity.org/2023/formulas/mathematics/college/sw8rfuyshx5hq4epbjfipdsap2d00m1xnl.png)
![y=-12](https://img.qammunity.org/2023/formulas/mathematics/high-school/k2n33xoaj12lhazoz0i27kg5lyoqgdl0fs.png)
We get the point (1.-12).
Set x = -1 and substitue in the given equation to find the point lie of the graph.
![(-1)y+12=0](https://img.qammunity.org/2023/formulas/mathematics/college/6s6xx8x3yqeq1ww56372dy4oqmn8mf24zs.png)
![-y+12=0](https://img.qammunity.org/2023/formulas/mathematics/college/zfqdq2vunislbpy8ykr4d7fxe43t7sn3pm.png)
Add y to both sides of the equation
![-y+12+y=0+y](https://img.qammunity.org/2023/formulas/mathematics/college/vdimsbmxcxrw4ivxgz8r1cevybpp42xfv5.png)
![12=y](https://img.qammunity.org/2023/formulas/mathematics/college/qfu5v4ytpf7dn8veg6zkzkaiad2jzpnr9q.png)
![y=12](https://img.qammunity.org/2023/formulas/mathematics/high-school/npvuecmko1t4czkcpngedi1egt976ujkvp.png)
We get (-1, 12).
The points (1,-12) and (-1,12) are lies on the graph of the given equation.
Final answer:
The graph of the equation.