To solve this question, follow the steps below.
Step 01: Find the maximum volume per day.
The maximum volume per day is when 5 hectoliters per minute are collected for 7.5 hours.
To find this volume, first, let's transform 5 hectoliters per minute into hectoliters per hour.
Knowing that 1 hour = 60 minutes:

Now, let's multiply by 7.5 hours to find how many hectoliters are collected per day:

Step 02: Transform the volume to liters.
Since 1 hectoliter = 100 liters.

Step 03: Find the number of bottles.
Since 1 bottle has 4.5 liters:

Answer: The maximum number of bottles the warehouse can receive in one day is 50,000.