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S= 4LW + 2WH; S=184, L = 9, W = 4.Surface area of a special rectangle box H=….?

User Katiak
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4.4k points

1 Answer

2 votes

Answer

H = 5

Step-by-step explanation

The surface area of the special rectangle box is given as

S = 4LW + 2WH

where

S = 184

L = 9

W = 4

We are then told to find H

To do that, we will just substitute for the variables whose numbers are given and solve for H

S = 4LW + 2WH

184 = 4×9×4 + 2×4×H

184 = 144 + 8H

We can rewrite this as

144 + 8H = 184

8H = 184 - 144

8H = 40

Divide both sides by 8

(8H/8) = (40/8)

H = 5

Hope this Helps!!!

User Mubeen Khan
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4.8k points