Question

6∆ - 10 + 2∆ = 38 solve.

Answer 1

We are given the following equation:

`6\Delta-10+2\Delta=38`

To find the value of delta, we need first to add line terms.

`8\Delta-10=38`

Now we need to add 10 on both sides:

`\begin{gathered} 8\Delta-10+10=38+10 \\ 8\Delta=48 \end{gathered}`

Now we divide both sides by 8

`\begin{gathered} (8\Delta)/(8)=(48)/(8) \\ \Delta=6 \end{gathered}`

The value of delta is 6