Question

A boat left a harbor and sailed 42 miles due north and then 35 miles due east. To the nearest mile, haw far away was the boat from the harbor?

Answer 1

In this case we can use the pythagorical theorem to find the distance so:

`x^2=42^2+35^2`

and we solve for x so:

`\begin{gathered} x=√(1764+1225) \\ x=\sqrt[]{2989} \\ x=54.67 \end{gathered}`

so he is at 54.67 miles