Question

Determine the maximum range a projectile would travel if its velocity at launch is 50 m/s at an angle of 40O above horizontal (assume the projectile lands at the same height it was launched).

Answer 1

The range of a projectile is given by:

`R=(v^2_0\sin 2\theta)/(g)`

where v0 is the initial velocity, theta is the angle and g is the acceleration of gravity. Plugging the values given we have that:

`\begin{gathered} R=((50)^2\sin (2\cdot40))/(9.8) \\ R=251.23 \end{gathered}`

Therefore the range is 251.23 meters