Question

A charge of 1.93 C is used to test the electric field of a central charge that causes a force of 245 N. What is the magnitude of the electric field?

Answer 1

The relation between the force, test charge and electric field is,

`E=(F)/(q)`

where F is the force, q is the charge and E is the electric field.

Substituting the known values,

`\begin{gathered} E=(245)/(1.93) \\ E=126.94NC^(-1) \end{gathered}`

Thus, the value of the magnitude of the electric field is 126.94 newton per coulomb.