INTRODUCTION
The blood group is given by three different alleles: A, B and O; where A and B have the same dominance and at the same time, both are dominant over the O allele. Therefore, the possible combinations of alleles and the resulting blood groups would be:
A/A: Blood Type A
A/B: Blood Type AB
B/B: Blood Type B
A/O: Blood Type A
B/O: Blood Type B
O/O: Blood Type O
QUESTIONS
1. Now we can do the punnet square for the cross between a homozygous type A individual (A/A) and a heterozygous type B individual (B/O); It should be noted that the second individual cannot have a B/B genotype because he would be homozygous:
2. Using the same information from the introduction and following the example of question 1 we can make another punnet square to answer the second question:
Parent 1 (Blood type AB) x Parent 2 (Blood type OO)
3. To answer question 3 we only have to cross two individuals heterozygous for blood types A and B (A/O and B/O) having a 25% chance of each blood type in the offspring: