1 Answer

Idali · Answer 1 · 2023-07-31T03:52:15+0000

Answer:

232.56M

The formula for calculating the molarity of the solution is expressed as:

$molarity=\frac{moles\text{ of solute}}{volume\text{ of solution}}$

Given the following parameters

moles of solute = 0.05moles

mass of solution (water) = 0.215g

Determine the volume of the solution

$\begin{gathered} volume=(mass)/(density) \\ volume\text{ of water}=(0.215g)/(1000gL^(-1)) \\ volume\text{ of water}=0.000215L \end{gathered}$

Determine the molarity of the solution

$\begin{gathered} molarity\text{ of the solution}=(0.05)/(0.000215) \\ molarity\text{ of the solution}=232.56M \end{gathered}$

Hence the molarity of a solution that contain 0.050 mol C12H22O11 in 0.215 g water is 232.56M