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Given that P(A AND B) = 0.29 and P(A | B) = 0.67, what is P(B)?Give your answer as a percent. Round to two decimal places.

Given that P(A AND B) = 0.29 and P(A | B) = 0.67, what is P(B)?Give your answer as-example-1

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According to the given problem,


\begin{gathered} P(A\cap B)=0.29 \\ P((A)/(B))=0.67 \end{gathered}

Consider the formula for conditional probability,


P((A)/(B))=(P(A\cap B))/(P(B))

Transposing the terms,


P(B)=(P(A\cap B))/(P((A)/(B)))

Substitute the values,


\begin{gathered} P(B)=(0.29)/(0.67) \\ P(B)=(29)/(67) \\ P(B)\approx0.4328 \\ P(B)\approx43.28\text{ percent} \end{gathered}

Thus, the required probability is 43.28% approximately.

User Martin Gunia
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