Given:
There are given that the first pool contains 1150 liters of water and the second pool contains 1300 liters of water.
Step-by-step explanation:
Let P1 represent the first pool and P2 represent the second pool and t is represent the time in minutes.
Then,
From the first pool:
![1150+30.5t](https://img.qammunity.org/2023/formulas/mathematics/college/1h5sd3uwiozym963blabv4drz5gyyim079.png)
And,
From the second pool:
![1300+24.25t](https://img.qammunity.org/2023/formulas/mathematics/college/32ohsw0ch3plvyx810quo4d039y5whok3e.png)
Now,
Equal both of the equations:
![\begin{gathered} 1,150+30.5t=1,300+24.25t \\ 1,150+30.5t-1,300-24.25t=0 \\ -150+6.25t=0 \\ -150=-6.25t \\ t=(150)/(6.25) \\ t=24 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/w808gh8mjafn1qvyn0k1iz5dm91qq8sjkx.png)
And,
The volume of the water in both of pool is:
![\begin{gathered} 1,150+30.5t=1,150+30.5\left(24\right) \\ =1150+732 \\ =1882 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/i92dgqihceku9p0sbfucet9hekqctzxgfx.png)
Final answer:
Hence, there are 24 minutes will the pools have the same amount of water and the volume of the water will be 1882 liters.