From the information given in the statement we know that:
• Triangle truck rentals charge ,$35 per day and 35 cents a, mile,.
,
• Circle rent a truck charge ,$60 a day and 30 cents a ,mile,.
On the other hand, let be x the number of miles he would need to drive in one day. So, we can write the following equation:
![\begin{gathered} \text{ Triangle truck rental charge }=\text{ Circle truck rental charge} \\ \text{\$}35+\text{\$}0.35x=\text{\$}60+\text{\$}0.30x \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/qdn3uhdf5lzmn6qfviwe2jyiiooix2f3j0.png)
Now, we can solve the equation for x
![\begin{gathered} \text{\$}35+\text{\$}0.35x=\text{\$}60+\text{\$}0.30x \\ \text{ Subtract \$}0.30x\text{ from both sides of the equation} \\ \text{\$}35+\text{\$}0.35x-\text{\$}0.30x=\text{\$}60+\text{\$}0.30x-\text{\$}0.30x \\ \text{\$}35+\text{\$}0.05x=\text{\$}60 \\ \text{ Subtract \$35 from both sides of the equation } \\ \text{\$}35+\text{\$}0.05x-\text{\$}35=\text{\$}60-\text{\$}35 \\ \text{\$}0.05x=\text{\$}25 \\ \text{ Divide by \$0.05 from both sides of the equation} \\ \frac{\text{\$}0.05x}{\text{\$}0.05}=\frac{\text{\$}25}{\text{\$}0.05} \\ \mathbf{x=500} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/rg3k69lvx8k6rkcfg3vnuke3x9sbghv90f.png)
Therefore, he would need to drive 500 thousand in one day for both companies to have the same total cost