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One number is 4 times a second number and their sum is 80. find the two numbers

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In order to find the two numbers mentioned we need to name them as variables, then,


\begin{gathered} number\text{ 1: }x \\ number\text{ 2: }y \end{gathered}

then, translate both sentences into equations,

one number is 4 times a second number:


x=4y

the sum of the numbers is 80:


x+y=80

then, replace the first equation into the second:


\begin{gathered} 4y+y=80 \\ solve\text{ }for\text{ }y \\ 5y=80 \\ y=(80)/(5) \\ y=16 \end{gathered}

find the value of x


\begin{gathered} x=4y \\ x=4*16 \\ x=64 \end{gathered}

Answer:

The numbers are 16 and 64.

User CennoxX
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