Given:
200 lottery tickets are sold for $2 each
winning ticket will get $83
To determine the expected value, we must the chance of winning the prize first:
The change of winning the price is 1/200.
So, the first expression would be:
![(83-2)((1)/(200))](https://img.qammunity.org/2023/formulas/mathematics/college/s5s43ahsflv8uu4u6zd46p4b8lidojmtwl.png)
Next, we determine the lose as well.
The chance to lose is (199/200). So the second expression is:
![-2((199)/(200))](https://img.qammunity.org/2023/formulas/mathematics/college/9rb7vre4wwnm8w9p15acsma6guh1v9fdc4.png)
Then, we combine the two expressions:
![\begin{gathered} (83-2)((1)/(200))-((2)(((199)/(200)) \\ \text{Simplify} \\ =(81)/(200)-(199)/(100) \\ =-1.585 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ocircw2d8h1xohktzksmu8ev0gvc7n6tg0.png)
Therefore, the expected value for a ticket is -$1.585 or the person is expected to lose $1.585.