Question

Select the equation that contains the points (-1, -8) and (3, 4).O y-4=3(x-3)O None of the other answers are correctO y+8=-2(x+1)O, y+4=3(x+3)Oy-4=-2(x-3)

Answer 1

We have to find the equation of the line that passes through the points (-1, -8) and (3, 4).

We can calculate the slope m as:

`m=(y_2-y_1)/(x_2-x_1)=(4-(-8))/(3-(-1))=(4+8)/(3+1)=(12)/(4)=3`

Then, we can write the equation in slope-point form as:

`\begin{gathered} y-y_0=m(x-x_0) \\ y-(-8)=3(x-(-1)) \\ y+8=3(x+1) \end{gathered}`

In this form, the equation does not match any of the options, but if we use the other point (3,4) to write the equation, we get another version:

`y-4=3(x-3)`

This match the first option.

Answer: y - 4 = 3(x - 3)