Question

Could you please help me and show how you arrived to your answer! I NEED HELPPP

Answer 1

Given:

Coordinate of point A is, A(-3,15).

Coordinate of point B is, B(9,11).

The objective is to find the coordinate of point P which is present at the ratio of 1:1 between A and B.

Consider the given ratio as

`m\colon n=1\colon1`

Consider the coordinate oa point A as,

`(x_1,y_1)=(-3,15)`

Consider the coordinate of point A as,

`(x_2,y_2)=(9,11)`

Then, the coordinate of point P can be calculated as,

`(x,y)=(\frac{m_{}x_2+nx_1}{m+n},\frac{m_{}y_2+ny_1}{m+n})`

Now, substitue all the given values in the above equation.

`\begin{gathered} (x,y)=((1(9)+1(-3))/(1+1),(1(11)+1(15))/(1+1)) \\ =((9-3)/(2),(11+15)/(2)) \\ =((6)/(2),(26)/(2)) \\ =(3,13) \end{gathered}`

Hence, the coordinate of the point P is (3,13).