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Find the variance of the following data. Round your answer to one decimal place. 6 7 8 9 10

User KevinH
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The equation to find the variance is :


s^2=\frac{\sum ^n_1(x-\bar{x})^2}{n-1}

So, first we will find the mean of the given data

The given data are : 6 , 7 , 8 , 9 , 10

mean = (6+7+8+9+10)/5 = 8

Then find ( x - x')

Variance =


\begin{gathered} ((6-8)^2+(7-8)^2+(8-8)^2+(9-8)^2+(10-8)^2)/(5-1) \\ \\ =((-2)^2+(-1)^2+(0)^2+(1)^2+(2)^2)/(5-1)=(4+1+0+1+4)/(4)=(10)/(4)=2.5 \end{gathered}

User Praneet Dixit
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