Question

15)The trajectory of a lacrosse ball thrown from a stick is given by the equationh=-16 + 110t + 7a) What is the starting height of the ball in its trajectory?b) What is the original upward velocity of the ball in its trajectory?

Answer 1

Step-by-step explanation

Part A

We are asked to find the starting height of the ball in its trajectory

To do so, let us first write the equation needed

`h=-16t^2+110t+7`

Next, we will substitute t =0 into the equation

`\begin{gathered} h=-16(0)^2+110(0)+7 \\ h=7 \end{gathered}`

Therefore the starting height will be 7

Part B

We are asked to obtain the original upward velocity of the ball

To do so, we will have to obtain the derivative

`h^(\prime)(t)=-32t+110`

Next, we will substitute t =0

`\begin{gathered} h^(\prime)(0)=-32(0)+110=110 \\ h^(\prime)(0)=110 \end{gathered}`

The original upward velocity is 110