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Given v = 60sinθ, what is the instantaneous voltage when θ = 610⁰?Question 1 options:56.38-20.52164.85-56.38

User Wes Gamble
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4.4k points

1 Answer

2 votes

We are given the following


v=60\sin \mleft(\theta\mright),\theta=610^(\circ\: )

we can also replace


\theta=610-360=250

then


\begin{gathered} v=60\sin \mleft(250^(\circ\: )\mright)=60\cdot(-0.93969) \\ v=-56.38155 \end{gathered}

Therefore, the answer is the last one

User Flows
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4.7k points