First, we have to analyze the meaning of the percentage m/m:
![\%m\text{/m = }\frac{g\text{ of substance F}}{g\text{ solution}}*100](https://img.qammunity.org/2023/formulas/chemistry/college/t10tzjy7v77z6nrpy8uo4llvo9i8ittzgr.png)
Then, we can calculate the required grams of the solution to carry out the reaction with substance F. We have to clear the equation in terms of the g solution as follows:
![\begin{gathered} g\text{ solution = }\frac{g\text{ substance F}}{\%m/m}*100 \\ \\ Replacing\text{ the values: } \\ \\ g\text{ solution= }\frac{4.62\text{ g}}{80.5}*100\text{ = 5.74 g} \end{gathered}](https://img.qammunity.org/2023/formulas/chemistry/college/t0b5x2wgtktyfjfjwpgbalbrqtmdkwzxlh.png)
Now, let's convert the mass of the solution into volume, using the solution's density (1.23g/ml):
![5.74\text{ g solution *}\frac{1\text{ ml solution}}{1.23\text{ g solution}}=\text{ 4.67 ml solution}](https://img.qammunity.org/2023/formulas/chemistry/college/tdcvmxylaa4v4fharz9g8z04m1yn9wdxds.png)
Then, the answer is that we need 4.67 ml of solution.