Question

Question number 4. The equation above it used along with it

Answer 1

Step-by-step explanation

Given

`4Ag+O_2\rightarrow2Ag_2O`

Mass of Ag2O = 200 g

Required: mass of oxygen

Solution

Step 1: Find the moles of Ag2O

n = m/M where n is the moles, m is the mass and M is the molar mass

n = 200g/231,735 g/mol

n = 0.863 mol

Step 2: Find the mass of oxygen

The molar ratio between Ag2O and O2 is 2:1

Therefore the moles of O2 = 0.863 x 2 = 1.726 mol

Step 3: Calculate the mass of oxygen

m = n x M

m = 1.726 mol x 31.998 g/mol

m = 54.4 g

Answer

Mass of oxygen = 54.4 g